In the given series $LCR$ circuit,if the value of $R$ is changed,then:

In a series $LCR$ circuit, the voltages across $L, C$, and $R$ are $50 \,V, 20 \,V$, and $40 \,V$ respectively. The $A.C.$ voltage applied across the combination of $LCR$ is: (in $\,V$)

The power factor of an $L-R$ series circuit is $0.6$ and that of a $C-R$ series circuit is $0.5$. If the elements ($L, C,$ and $R$) of the two circuits are joined in series,the power factor of this circuit is found to be $1$. The ratio of the resistance in the $L-R$ circuit to the resistance in the $C-R$ circuit is:

In the series $L-C-R$ circuit shown,the impedance is (in $\Omega$)

Consider the parallel $LCR$ circuit shown in the figure. Find the net current $i$ and the phase of $i$. Show that $i = \frac{V}{Z}$. Find the impedance $Z$ for this circuit.

In an $LCR$ circuit,$R = 100 \ \Omega$. When the capacitor $C$ is removed,the current lags behind the voltage by a phase of $\pi / 3$. When the inductor $L$ is removed,the current leads the voltage by a phase of $\pi / 3$. What is the impedance of the circuit in $\Omega$?